Upgrade Disable Compromise

[Darkas]

Dude, are you kidding me :P?

I'm kinda over math 101, and mine are consistently correct.

I encourage you to reread my statement, I did write "chance of winning", I know that dice throws are independent, thanks !

If you need the maths, given 47.1, it's 1-(1-0.471)^2*100%.
Same for 7v8, 1-(1-0.274)^2*100%.

The chance of winning the battle with to roll instead of one is definitely 1-(1-p)^2*100%, where p is the probability of winning. If you want more explanation on that, do not hesitate to ask.

The good question however is the "Where does your 47.1/27.4 come from", and the answer is that I computed the probability the other day.

If you want more infos on that, just ask (I basically computed all permutation of 1 to 8 dices, and sum up all the combinations of battle results for each type of combat, and added the possibility to see how bonuses and maluses change that. It's determinist and exact results (in the given precision, which is derived from BigDecimal scale, up to infinity), it's not simulation-based (what I previously did, far easier but less precise and far less efficient)).

[techgump]

VW is not using 1-8 die.

[Darkas]

Can you read before react ?

1 to 8 dices, I know it's D6. But you can have up to 8 units =)

[techgump]

I basically computed all permutation of 1 to 8 dices

You words.

If you want more infos on that, just ask

my question, as I did ask:

1. where does "47.1%" come from too?

No need to get overly defensive here.

[techgump]

Mind posting your math computations for us to see. Txs.

The chance of winning the battle with to roll instead of one is definitely 1-(1-p)^2*100%, where p is the probability of winning. If you want more explanation on that, do not hesitate to ask.

Sure please explain where this comes from.

[techgump]

Some info on law of averages, as mentioned in the previous link I provided regarding dice odds.
http://en.wikipedia.org/wiki/Law_of_averages

[Darkas]

You should stop stating things you obviously don't know using some random wiki links, no offense.

If you want some start here.

It's very easy to actually compute it:

The chance of winning a battle is 1 - the chance of losing it.

You have to lose both fight to lose the combat, in other word the defender have to win both fights.

If your chance of winning is p, the defender's are 1-p. So for him to win both is (1-p)*(1-p)=(1-p)^2

Therefore the chance that you win is 1-(1-p)^2, times 100% if you want percent units.

For the other question, it's easy to do (inefficiency) like that:

Code: Select all

def computeBruteforceTables(): Unit = {
    for (k <- 0 until 6) {
      for (l <- 0 until 6) {
        for (m <- 0 until 6) {
          for (n <- 0 until 6) {
            for (o <- 0 until 6) {
              for (p <- 0 until 6) {
                for (q <- 0 until 6) {
                  for (r <- 0 until 6) {
                    if (k == 0) {
                      if (l == 0) {
                        if (m == 0) {
                          if (n == 0) {
                            if (o == 0) {
                              if (p == 0) {
                                if (q == 0) {
                                  array1(r) += 1
                                }
                                array2(q + r) += 1
                              }
                              array3(p + q + r) += 1
                            }
                            array4(o + p + q + r) += 1
                          }
                          array5(n + o + p + q + r) += 1
                        }
                        array6(m + n + o + p + q + r) += 1
                      }
                      array7(l + m + n + o + p + q + r) += 1
                    }
                    array8(k + l + m + n + o + p + q + r) += 1
                  }
                }
              }
            }
          }
        }
      }
    }

The harder part is actually what follows =)

[techgump]

You should stop stating things you obviously don't know using some random wiki links, no offense.

This statement does not do anything to prove your point. I am providing references to my point, a typical part of validating a statement. Your dismissal of such makes no sense. I would love to see your references as well.

And like I asked, lets see your math for VW. Not some code byte without relation to computation, where it came from, and not using VW variables. Txs.

[Lopdo]

heh, when he shows you his math, you ask him to explain it, when he explains it, you ask him to show you some math.
I suspect that his references could be found in university degree of some sort

You don't have to use specific variables to prove your point but I must admit code he posted is useless for almost everyone here

[Darkas]

The "bytecode" which is actually some highlevel stuff, but whatever, is just 8 for loop going from 0 to 5 and filling some array, which is kinda easy to read "approximately" if you're some knowledge in applied math/computer science.

You asked me:

I basically computed all permutation of 1 to 8 dices

You words.

I just give you a little bit more than words, but yeah, can't do more.

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I thing what I said is clear, maybe some other people could answer to this, the only thing I can do is to recommend to reread my posts.


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And like I asked, lets see your math for VW. Not some code byte without relation to computation, where it came from, and not using VW variables. Txs.

Are you talking about the reroll thing, or the plain probability of winning a fight?